| The Driven LRC Circuit
When a driving force is applied to the circuit, the circuit will oscillate
at the same frequency as the driving force; however, the amplitude of the
oscillations depends on the driving frequency. When the frequency is low,
the capacitor has more time to charge and offers a large effective
resistance to the flow of current. When the frequency is high, the
inductor produces a large induced EMF, which again offers a large
effective resistance. The total impedance of the system is minimum at the
natural frequency of the system, given by Eq.1.
Select one of the available resistors and add it to your circuit as in
Figure 1. Switch the signal generator to sine-wave mode. Using the
appropriate combination of the push=button and dial settings, set the
frequency of the signal generator to the natural oscillation frequency you
measured above. Connect your
oscilloscope leads to either side of the resistor and view the
signal on the oscilloscope. Since V=IR for the resistor, the
resistor voltage is proportional to the current. Adjust the of the
resistor voltage 1 V.
(Remember that amplitude is 0 to max; however, it may be easier to set min
to max to 2 V.)
Now try adjusting the frequency of the signal generator. Find the
resonant frequency, the frequency where the current is largest. Record
this frequency and VR at resonance.
Resonant frequency: fres =
Hz.
VR at resonance =
V.
With the circuit at resonance, measure the voltages across the signal
generator, the capacitor, and the inductor individually.
EMF at resonance =
V. (Voltage across the signal generator.)
VL at resonance =
V.
VC at resonance =
V.
Note that at resonance, VR should equal the EMF, and VL should
equal VC as long as the resistance of the
inductor can be neglected. This should be clear by considering the phasor
diagram of these voltages at resonance.
Figure 2
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