Hint 11.5

The following integrals may be useful:

∫ sin²(kx) dx = x/2 - sin(kx)cos(kx)/(2k)

∫ cos²(kx) dx = x/2 + sin(kx)cos(kx)/(2k)

∫ sin(kx) cos(kx) dx = 1/(2k) - cos²(kx)/(2k)

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