7-QT2. Are the bases of convective clouds generally higher during the day or the night? Explain.
At night, because of lower temperatures at the surface, the difference between the dew point and the surface temperature is smaller than during the day. Therefore an air parcel need not rise so high for it to become saturated. If convection is able to occur, the cloud bases will therefore be lower at night. 7-QT4. Use Fig. 5.11, p.111 (Chapter 4), to help you explain why the bases of cumulus clouds, which form from rising thermals during the summer, increase in height above the surface as you move due west of a line that runs north-south through central Kansas.
West of the described line, average summer water vapor pressure decreases rapidly to the west and therefore the dew point and relative humidity drops to the west. Since the height of convective cloud bases is proportional to the difference in the temperature and the dew point (see the box on p.172), the height of cumulus bases increases to the west. 7-QT5. For least polluted conditions, what would be the best time of day for a farmer to burn agricultural debris?
7-PE2. If the height of a cumulus cloud is 1000 meters above the surface, and the dew point at the earth's surface beneath the cloud is 20EC, determine the air temperature at the earth's surface beneath the cloud.
For least pollution the farmer should burn his debris at that time of day most favorable for convection, i.e., at that time when the atmosphere is least stable. That tends to be the case at the warmest time of day. Thus the farmer should burn his debris at the warmest time of day, probably from mid to late afternoon.
7-PE3. The condensation level over New Orleans, Louisiana, on a warm muggy afternoon is 2000 feet. If the dew point of the rising air at this level is 73EF, what is the approximate dew point and air temperature at the surface? Determine the surface relative humidity. (Hint: See Chapter 5, p.117.)
The dew-point lapse rate is 2EC/km, hence the temperature at the cloud base is 18EC. Since the dry adiabatic rate is 10EC/km, the temperature at the surface is therefore 18EC+10EC=28EC.
7-PE5. In Fig.7.26, above, a radiosonde is released and sends back temperature data as shown in the diagram. (This is the environment temperature.) (a) Calculate the environmental lapse rate from the surface up to 3000 m. (b) What type of atmospheric stability does the sounding indicate?
Since the dew-point lapse rate is 2EC/km=1EF/1000 ft, the dew point at the surface is Tdew=73EF+2EF=75EF. Since the dry adiabatic rate is approximately 5.5EF/1000 ft, the temperature at the surface is T=73EF+2×5.5EF=84EF. Hence the vapor pressure at the surface, which is equal to the saturation vapor pressure at 75EF is (from Table 1 on p.117) e=29.6 mb. The saturation vapor pressure at the surface (84EF) is (from Table 1 on p.117) es=39.8 mb. Thus the relative humidity is RH=e/es=29.6 mb/39.8 mb=74%.
(a) ELR =DT/h = [10EC-(-14EC)]/3000 m = 8EC/km. (b) 8EC is between the dry adiabatic rate and the moist adiabatic rate. Hence the atmosphere is conditionally stable. (c) The vapor pressure at the surface, which is equal to the saturation vapor pressure at the dew point of 2EC is (from Table 1 on p.117) e = 6.9 mb. The saturation vapor pressure at the surface (10EC) is (from Table 1 on p.117) es = 12.3mb. Thus the relative humidity is RH = e/es = 6.9 mb/12.3 mb = 56%. (d) Since the dry adiabatic rate and the dew-point lapse rate close at 8EC/km and since the temperature and the dew point differ by 8EC (10EC-2EC) at the surface, the height of the condensation level is approximately h = 1 km = 1000 m. (e) At the cloud base, the temperature will have dropped by 10EC from the surface, hence Tbase= 0EC. (f) T(3000 m)=0EC-2000 m×6EC/1000 m = -12EC. (g) The inside temperature (-12EC) is higher than the outside temperature (-14EC). This suggests buoyancy for the rising moist parcel, i.e., conditional instability. (h) As explained in part (g) the parcel would continue to rise and therefore to develop vertically. (i) This would be a cumulus congestus cloud. (j) Tbase= -12EC+3 km×10EC/km = 18EC, Tdew,base = -12EC+3 km×2EC/km = -6EC. (k) RH = e/es = 4.0 mb/21.0 mb = 19%. (l) Latent heat released during condensation causes the air to be warmer on the leeward side. (m) Water vapor removed from the air by precipitation on the windward side causes the air to be drier on the leeward side.