Absolute Determination of Stellar Coordinates
Three instruments are required:
(a) clock,
(b) meridian telescope,
(c) zenith telescope.I. Right Ascension (α) Determination - Use a sidereal clock and a meridian
telescope. When a star transits (crosses the celestial meridian), its right
ascension equals the local sidereal time, i.e., α = LST. Refraction has no
effect on the determined value of α, but the result must be corrected for
stellar aberration.II. Declination (δ) Determination - Again use a meridian telescope. When a star
transits, thenhc = 90° - φ + δ, or δ = hc + φ - 90°.
Of course, to get accurate results for δ, the observer must (1) know his
or her latitude, (2) correct for stellar aberration and (3) correct for
refraction.III. Latitude (φ) Determination (3 methods) -
(1) Observation of a common star from multiple sites. (For purposes of illustration
it is assumed that two sites and the north pole lie on a common great circle.
This makes the illustration of the method very simple. In practice three or more
sites are used and the method, although conceptually similar, yields messier
equations.)Observations of the altitude of culmination for a common star are made
from both sites. From either of the two illustrated sites, hc = 90° - φ + δ. If the north pole
moves along the common great circle arc, then Δφa = - Δφb. (For motions of the pole in the
orthogonal direction, to first order, Δφa = Δφb = 0.) If, over the period of time in which the north
pole moves, the star also moves in declination by Δδ, then Δhca = -Δφa + Δδ and
Δhcb = -Δφb + Δδ. But Δφa = - Δφb, so Δφa = (Δhcb - Δhca)/2, Δφb = (Δhca - Δhcb)/2 and
Δδ = (Δhca + Δhcb)/2. Hence variations in the latitudes of the observing sites (or, equivalently,
polar motion) as well as the declination of the observed star can be determined. Hence method (1)
yields changes to a previously
determined latitude.
(2) Use a zenith telescope and a star of known declination which culminates very nearly
at the zenith. The center of the field of view of the telescope, as shown at the right
is the zenith. As the star culminates, with respect to the southern horizon, yielding
hcs, the telescope is quickly rotated through 180° about its vertical axis which then
yields the altitude of culmination with respect to the northern horizon, hcn. Then Δh = hcn - hcs, can
be determined (with much greater accuracy than either hcn or hcs.) But hcs = 90° - φ + δ, and
hcn = 180° - hcs = 90° + φ - δ. So φ = δ + ½(hcn - hcs) = δ + ½Δh.(3) Use a meridian telescope and any circumpolar star. Let hu = φ + 90° - δ be the altitude (with respect
to the north point of the horizon) of upper culmination and hl = φ - 90° + δ be the altitude of lower
culmination. It follows by adding these two relationships that φ = ½(hu + hl).
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